(X+2)^3-(x-1)=x(3x+4)+8

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Solution for (X+2)^3-(x-1)=x(3x+4)+8 equation: 



(X+2)^3-(X-1)=X(3X+4)+8

We move all terms to the left:

(X+2)^3-(X-1)-(X(3X+4)+8)=0

We get rid of parentheses

(X+2)^3-X-(X(3X+4)+8)+1=0



We calculate terms in parentheses: -(X(3X+4)+8), so:

X(3X+4)+8

We multiply parentheses

3X^2+4X+8

Back to the equation:

-(3X^2+4X+8)



We add all the numbers together, and all the variables

-1X+(X+2)^3-(3X^2+4X+8)+1=0

We get rid of parentheses

-3X^2-1X+(X+2)^3-4X-8+1=0

We add all the numbers together, and all the variables

-3X^2-5X+(X+2)^3-7=0

We move all terms containing X to the left, all other terms to the right

-3X^2-5X+(X+2)^3=7

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